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The Lumenary

Practice · Grades 9–12

Complex numbers

Complex numbers

Warm-upHuman

Compute (4−3i)(2+5i)(4 - 3i)(2 + 5i) and enter its real part.

Complex numbers

Warm-upHuman

What is i2027i^{2027}?

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Complex numbers

Warm-upHuman

Compute ∣(3+4i)(5−12i)∣\left|(3 + 4i)(5 - 12i)\right| — ideally without multiplying out first.

Complex numbers

CoreHuman

Which is the polar form of z=−1+i3z = -1 + i\sqrt 3?

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Complex numbers

CoreHuman

Solve z2−4z+13=0z^2 - 4z + 13 = 0.

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Complex numbers

CoreHuman

Which of the following are sixth roots of unity, i.e. solutions of z6=1z^6 = 1? (Choose all that apply.)

Choose all that apply

Complex numbers

StretchHuman

What is wrong with this "proof" that 1=−11 = -1? 1=1=(−1)(−1)=−1 −1=i⋅i=−1.1 = \sqrt 1 = \sqrt{(-1)(-1)} = \sqrt{-1}\,\sqrt{-1} = i \cdot i = -1.

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Complex numbers

CoreFormal

In the Lean module, cis θ means cos⁡θ+isin⁡θ\cos\theta + i\sin\theta and n : ℕ. Which Lean statement is De Moivre's theorem?

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Complex numbers

StretchComputational

Write nth_roots(w, n) that returns a list of the nn complex nn-th roots of a non-zero complex number w, using polar form: if w=Rcis⁡φw = R\operatorname{cis}\varphi, the roots are R1/ncis⁡φ+2πknR^{1/n}\operatorname{cis}\frac{\varphi + 2\pi k}{n} for k=0,…,n−1k = 0, \dots, n-1. Python's cmath.polar(w) returns (R,φ)(R, \varphi) and cmath.rect(r, theta) returns rcis⁡θr\operatorname{cis}\theta.

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