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The Lumenary

Practice · Advanced undergraduate

Differential geometry of curves and surfaces

Differential geometry of curves and surfaces

Warm-upHuman

A running track has semicircular ends of radius 36.536.5 m. Along the straight parts the curvature is 00. What is the curvature on the bends?

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Differential geometry of curves and surfaces

Warm-upHuman

Which of these surfaces have Gaussian curvature K=0K = 0 at every point? (Choose all that apply.)

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Differential geometry of curves and surfaces

CoreHuman

For the cylinder of radius 22, X(θ,z)=(2cos⁡θ,2sin⁡θ,z)X(\theta, z) = (2\cos\theta, 2\sin\theta, z), one finds E=4E = 4, F=0F = 0, G=1G = 1, L=−2L = -2, M=0M = 0, N=0N = 0. What are KK and HH?

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Differential geometry of curves and surfaces

CoreHuman

The helix γ(s)=(3cos⁡(s/5),3sin⁡(s/5),4s/5)\gamma(s) = (3\cos(s/5), 3\sin(s/5), 4s/5) has unit speed (check: 32+42=523^2 + 4^2 = 5^2), curvature κ=a/c2\kappa = a/c^2 and torsion τ=b/c2\tau = b/c^2 with a=3a = 3, b=4b = 4, c=5c = 5. Compute 1κ2+τ2\dfrac{1}{\kappa^2 + \tau^2}.

Differential geometry of curves and surfaces

CoreHuman

A triangle on a sphere of radius RR is bounded by three great-circle arcs and has angles 100∘100^\circ, 80∘80^\circ and 90∘90^\circ. By Girard's theorem its area is R2R^2 times its angle excess (in radians). What is the angle excess, in degrees?

Differential geometry of curves and surfaces

CoreHuman

A closed orientable surface of genus 33 (a pretzel with three holes) sits in R3\mathbb{R}^3. Its total curvature ∬K dA\iint K\, dA equals mπm\pi for which integer mm?

Differential geometry of curves and surfaces

CoreHuman

Why can a flat sheet of paper be rolled into a cylinder without stretching or tearing, but not wrapped smoothly around a ball?

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Differential geometry of curves and surfaces

CoreFormal

The Lean theorem sphere_gauss_curvature has the hypothesis hφ : cos φ ≠ 0. Why is it needed?

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Differential geometry of curves and surfaces

CoreComputational

Write signed_curvature(dx, dy, ddx, ddy) returning the signed curvature κ=(x′y′′−y′x′′)/(x′2+y′2)3/2\kappa = (x'y'' - y'x'')/(x'^2 + y'^2)^{3/2} of a plane curve at a point, given the values of x′,y′,x′′,y′′x', y', x'', y'' there. Then use it to find the curvature of the ellipse (3cos⁡t,sin⁡t)(3\cos t, \sin t) at t=0t = 0 and t=π/2t = \pi/2.

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Differential geometry of curves and surfaces

StretchHuman

Why must every torus in R3\mathbb{R}^3, however it is shaped, have points of negative Gaussian curvature?

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