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Derived categories

Derived categories

Warm-upHuman

Which of these chain maps are quasi-isomorphisms? (Complexes of abelian groups; a single group means a complex concentrated in degree 00. Choose all that apply.)

Choose all that apply

Derived categories

Warm-upHuman

Compute the order of Ext⁡Z1(Z/12,Z/18)\operatorname{Ext}^1_{\Z}(\Z/12, \Z/18).

Derived categories

Warm-upHuman

The derived tensor product Z/8⊗ZLZ/12\Z/8 \otimes^{L}_{\Z} \Z/12 is an object of D(Ab)D(\mathrm{Ab}). What is the order of its cohomology group in degree −1-1?

Derived categories

CoreHuman

Which of these Hom-groups in D(Ab)D(\mathrm{Ab}) are non-zero? (Choose all that apply.)

Choose all that apply

Derived categories

CoreHuman

Let R=Z/4R = \Z/4. What is the order of Hom⁡D(R)(Z/2,Z/2[5])=Ext⁡R5(Z/2,Z/2)\operatorname{Hom}_{D(R)}(\Z/2, \Z/2[5]) = \operatorname{Ext}^5_R(\Z/2, \Z/2)?

Derived categories

CoreHuman

In the proof of Lemma 2 (Hom⁡K(P,Z)=0\operatorname{Hom}_K(P, Z) = 0 for PP a bounded-above complex of projectives and ZZ acyclic), we put g=fn−hn+1dPg = f^n - h^{n+1} d_P. Where is the projectivity of PnP^n used?

Choose one

Derived categories

CoreHuman

Let p:P=(Z→2Z)→Z/2p : P = (\Z \xrightarrow{2} \Z) \to \Z/2 be the resolution map. Which statement is correct?

Choose one

Derived categories

StretchHuman

“Every object XX of Db(A)D^b(\mathcal{A}) is isomorphic to ⨁nHn(X)[−n]\bigoplus_n H^n(X)[-n].” Which hypothesis on A\mathcal{A} makes this true, together with an example showing that some hypothesis is needed?

Choose one

Derived categories

CoreFormal

Which Lean statement formalises “homotopic chain maps become equal in the derived category”? (Here f g : K ⟶ L are maps of cochain complexes and Q is DerivedCategory.Q.)

Choose one

Derived categories

StretchComputational

Write ext_orders(a, b) returning the list [|Ext^0|, |Ext^1|, |Ext^2|] for Ext⁡Zn(Z/a,Z/b)\operatorname{Ext}^n_{\Z}(\Z/a, \Z/b), computed from the resolution 0→Z→aZ→Z/a→00 \to \Z \xrightarrow{a} \Z \to \Z/a \to 0: apply Hom⁡(−,Z/b)\operatorname{Hom}(-, \Z/b) to get Z/b→aZ/b\Z/b \xrightarrow{a} \Z/b and count the kernel and the cokernel of x↦ax mod bx \mapsto ax \bmod b (do not use gcd).

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