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The Lumenary

Practice · First-year graduate

Homological algebra

Homological algebra

Warm-upHuman

Consider the chain complex 0→Z→d2Z2→d1Z→00 \to \mathbb{Z} \xrightarrow{d_2} \mathbb{Z}^2 \xrightarrow{d_1} \mathbb{Z} \to 0 with d2(n)=(2n,4n)d_2(n) = (2n, 4n) and d1(a,b)=2a−bd_1(a, b) = 2a - b. How many elements does H1=ker⁡d1/im⁡d2H_1 = \ker d_1 / \operatorname{im} d_2 have?

Homological algebra

Warm-upHuman

Which statements about chain maps are true in general? (Choose all that apply.)

Choose all that apply

Homological algebra

CoreHuman

How many elements does Tor1Z(Z/12,Z/18)\mathrm{Tor}_1^{\mathbb{Z}}(\mathbb{Z}/12, \mathbb{Z}/18) have?

Homological algebra

CoreHuman

How many equivalence classes of extensions 0→Z/5→E→Z/5→00 \to \mathbb{Z}/5 \to E \to \mathbb{Z}/5 \to 0 of abelian groups are there?

Homological algebra

CoreHuman

In the existence part of the comparison theorem, why does fnd:Pn+1→Qnf_n d : P_{n+1} \to Q_n land in ker⁡(d:Qn→Qn−1)\ker(d : Q_n \to Q_{n-1}) (for n≥1n \geq 1)?

Choose one

Homological algebra

StretchHuman

Apply −⊗Z/2- \otimes \mathbb{Z}/2 and its derived functors to 0→Z→2Z→Z/2→00 \to \mathbb{Z} \xrightarrow{2} \mathbb{Z} \to \mathbb{Z}/2 \to 0. The long exact sequence reads Tor1(Z,Z/2)→Tor1(Z/2,Z/2)→∂Z/2→2Z/2→Z/2→0\mathrm{Tor}_1(\mathbb{Z}, \mathbb{Z}/2) \to \mathrm{Tor}_1(\mathbb{Z}/2, \mathbb{Z}/2) \xrightarrow{\partial} \mathbb{Z}/2 \xrightarrow{2} \mathbb{Z}/2 \to \mathbb{Z}/2 \to 0. What is Tor1(Z/2,Z/2)\mathrm{Tor}_1(\mathbb{Z}/2, \mathbb{Z}/2)?

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Homological algebra

CoreFormal

Which Lean statement says that the extension 0→Z→2Z→Z/2→00 \to \mathbb{Z} \xrightarrow{2} \mathbb{Z} \to \mathbb{Z}/2 \to 0 does not split (as proved in not_split)?

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Homological algebra

StretchComputational

A chain complex 0→C2→d2C1→d1C0→00 \to C_2 \xrightarrow{d_2} C_1 \xrightarrow{d_1} C_0 \to 0 of free abelian groups is given by integer matrices d2 (shape dim⁡C1×dim⁡C2\dim C_1 \times \dim C_2) and d1 (shape dim⁡C0×dim⁡C1\dim C_0 \times \dim C_1), as lists of rows. Write betti_mod_p(d2, d1, p) returning [b0, b1, b2], the dimensions of Hn(C⊗Fp)H_n(C \otimes \mathbb{F}_p) for a prime pp, using bn=dim⁡Cn−rank⁡dn−rank⁡dn+1b_n = \dim C_n - \operatorname{rank} d_n - \operatorname{rank} d_{n+1} over Fp\mathbb{F}_p (with d0=d3=0d_0 = d_3 = 0).

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