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The Lumenary

Practice · Advanced undergraduate

Mathematical biology

Mathematical biology

Warm-upHuman

For the logistic map xn+1=2.5 xn(1−xn)x_{n+1} = 2.5\,x_n(1 - x_n), what is the non-zero fixed point, in percent of the maximum population?

Mathematical biology

CoreHuman

For which growth rates rr is the non-zero fixed point x∗=1−1/rx^* = 1 - 1/r of the logistic map locally asymptotically stable? (Choose all that apply.)

Choose all that apply

Mathematical biology

Warm-upHuman

In the simple SIR model, an infection has R0=4R_0 = 4. What percentage of the population must be immune for an introduced infection not to grow (the herd immunity threshold)?

Mathematical biology

Warm-upHuman

Which statement about the basic reproduction number R0=β/γR_0 = \beta/\gamma is correct?

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Mathematical biology

CoreHuman

At the coexistence equilibrium of the Lotka–Volterra predator–prey model the Jacobian has eigenvalues ±iαγ\pm i\sqrt{\alpha\gamma}. What can we conclude from the linearisation alone?

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Mathematical biology

CoreHuman

In the competition model x′=x(1−x−a12y)x' = x(1 - x - a_{12}y), y′=y(1−y−a21x)y' = y(1 - y - a_{21}x), which parameters give a stable coexistence equilibrium?

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Mathematical biology

CoreHuman

A fish stock grows logistically with r=0.4r = 0.4 per year and carrying capacity K=10 000K = 10\,000 tonnes, and is harvested at a constant rate of HH tonnes per year. What is the largest HH for which a positive equilibrium exists (the maximum sustainable yield), in tonnes per year?

Mathematical biology

StretchHuman

In the SIR model with R0>1R_0 > 1 and almost everyone initially susceptible, when does the number of infected people reach its maximum?

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Mathematical biology

CoreFormal

Which Lean statement says that Volterra's quantity is conserved along a solution of the predator–prey equations at time t?

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Mathematical biology

StretchComputational

Write final_size(R0) returning the fraction 1−s1 - s of a population eventually infected in the SIR model, where s∈(0,1)s \in (0, 1) solves s=e−R0(1−s)s = e^{-R_0(1 - s)} (return 0.0 when R0≤1R_0 \le 1). Use bisection on g(s)=s−e−R0(1−s)g(s) = s - e^{-R_0(1 - s)}. Since g(1)=0g(1) = 0 as well, bracket the non-trivial root in [0,1/R0][0, 1/R_0], where g(0)<0<g(1/R0)g(0) < 0 < g(1/R_0).

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