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The Lumenary

Practice · Early undergraduate

Non-Euclidean geometry: spherical and hyperbolic

Non-Euclidean geometry: spherical and hyperbolic

Warm-upHuman

A pilot flies from the North Pole due south to the equator, turns to fly a quarter of the way around the equator, and then flies due north back to the pole. What is the angle sum of this triangle, in degrees?

Non-Euclidean geometry: spherical and hyperbolic

Warm-upHuman

A triangle on a sphere of radius 22 has angles π2\frac{\pi}{2}, π2\frac{\pi}{2} and π3\frac{\pi}{3}. Its area is kπ3\frac{k\pi}{3}. What is kk?

Non-Euclidean geometry: spherical and hyperbolic

CoreHuman

A triangle in the hyperbolic plane (curvature −1-1) has three angles of π6\frac{\pi}{6} each. What is its area?

Choose one

Non-Euclidean geometry: spherical and hyperbolic

CoreHuman

Which of these curves are lines (geodesics) of the upper half-plane model H\mathbb H? (Choose all that apply.)

Choose all that apply

Non-Euclidean geometry: spherical and hyperbolic

CoreHuman

What is the hyperbolic distance in H\mathbb H between ii and e3ie^3 i?

Non-Euclidean geometry: spherical and hyperbolic

CoreHuman

In the theorem that g(z)=az+bcz+dg(z) = \frac{az + b}{cz + d} is an isometry of H\mathbb H we required a,b,c,da, b, c, d real with ad−bc=1ad - bc = 1. What goes wrong for g(z)=−zg(z) = -z, which has a=−1a = -1, b=c=0b = c = 0, d=1d = 1 and ad−bc=−1ad - bc = -1?

Choose one

Non-Euclidean geometry: spherical and hyperbolic

CoreFormal

The Lean theorem many_parallels states: for c : ℝ with 1 ≤ c and y : ℝ with 0 < y, normSq (I * y - c) ≠ normSq (1 + I - c). What does it say geometrically?

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Non-Euclidean geometry: spherical and hyperbolic

StretchHuman

Why does the upper half-plane model show that the parallel postulate cannot be proved from the other axioms of plane geometry?

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Non-Euclidean geometry: spherical and hyperbolic

StretchComputational

Write hyp_dist(z, w) for points of the upper half-plane (Python complex numbers with positive imaginary part), using cosh⁡d=1+∣z−w∣22Im⁡zIm⁡w\cosh d = 1 + \frac{|z - w|^2}{2\operatorname{Im} z \operatorname{Im} w}, and defect(z1, z2, z3), the defect π−(α+β+γ)\pi - (\alpha + \beta + \gamma) of the triangle, computing each angle from the side lengths by the hyperbolic law of cosines cos⁡γ=cosh⁡acosh⁡b−cosh⁡csinh⁡asinh⁡b\cos\gamma = \frac{\cosh a \cosh b - \cosh c}{\sinh a \sinh b} (where cc is the side opposite γ\gamma).

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